Question 209912
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Let *[tex \Large s] represent the number of student tickets sold.  Let *[tex \Large a] represent the number of adult tickets sold.  Making the leap of faith that no one besides students and adults attended the game (no little kids, 17-year old high school graduates, or space aliens were counted in the total of 400 that was given), then you can say that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ s + a = 400]


Since student tickets cost $2, the amount of money received from the sale of student tickets must be *[tex \Large 2s].  Likewise the amount of money received from the sale of adult tickets must be *[tex \Large 3a].  The sum of these two amounts is the total ticket sales of $1050, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2s + 3a = 1050]


Solve the first equation for *[tex \Large a]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a = 400 - s]


Substitute this expression for *[tex \Large a] in the second equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2s + 3(400 - s) = 1050]


Solve for *[tex \Large s], then using the value of *[tex \Large s], solve the first equation for *[tex \Large a].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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