Question 209914
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Let *[tex \Large x] represent the length of the pool table, then the width is *[tex \Large \frac{x}{2}] because the length is twice the width meaning the width is half of the length.  The perimeter of a rectangle is two times the length plus 2 times the width, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x + 2(\frac{x}{2}) = 30]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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