Question 29033
Here's one approach:

First, find the slope of the line using two of the known points.
Then you can use the slope formula{{{m = (y2-y1)/(x2-x1)}}} to find the value of n.

{{{m = (y2-y1)/(x2-x1)}}} Use the points (6, 3) and (-3, -3) as (x1, y1) and (x2, y2)

{{{m = (-3-3)/(-3-6)}}}
{{{m = (-6)/(-9)}}}
{{{m = 2/3}}}

Now use the slope formula again, only this time, use the point (n, -1) as one of the two points. The other point can be either one of the other two. Use (6, 3). Using (n, -1) and (6, 3)

{{{m = (3-(-1))/(6-n)}}}
{{{m = 4/(6-n)}}} But {{{m = 2/3}}}, so
{{{4/(6-n) = 2/3}}} Multiply both sides by (6-n)
{{{4 = 2(6-n)/3}}} Multiply both sides by 3.
{{{12 = 2(6-n)}}} Divide both sides by 2.
{{{6 = 6-n}}} Subtract 6 from both sides.
{{{0 = -n}}} or {{{n = 0}}}