Question 209732
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(0,-3\right)]. So this means that {{{x[1]=0}}} and {{{y[1]=-3}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-8,0\right)].  So this means that {{{x[2]=-8}}} and {{{y[2]=0}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(0--3)/(-8-0)}}} Plug in {{{y[2]=0}}}, {{{y[1]=-3}}}, {{{x[2]=-8}}}, and {{{x[1]=0}}}



{{{m=(3)/(-8-0)}}} Subtract {{{-3}}} from {{{0}}} to get {{{3}}}



{{{m=(3)/(-8)}}} Subtract {{{0}}} from {{{-8}}} to get {{{-8}}}



{{{m=-3/8}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(0,-3\right)] and *[Tex \LARGE \left(-8,0\right)] is {{{m=-3/8}}}