Question 209750
(e^2x) - (3e^x) + 2 = 0
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It may not look like but this is a quadratic equation.
(e^x)^2 - 3e^x + 2 = 0
Factor to get:
(e^x-2)(e^x-1) = 0
e^x = 2 or e^x = 1
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Take the natural log of each to solve for "x":
x = ln(2) or x = ln(1)
x = 0.6931.. or x = 0
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Cheers,
Stan H.
Reply to stanbon@comcast.net