Question 209715
ln(x+1)^2=2 
i worked it out as:
ln(x+1)^2=2
(x+1)^2=e^2  You changed from exponent 2 to multiply by 2
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2(x+1)=7.38906
2x+2=7.38906
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ln(x+1)^2=2
2ln(x+1) = 2
ln(x+1) = 1
x+1 = e
x = e-1