Question 209635
x+y=6 
x=6-y
xy=(10x+y)/3
(6-y)y=(10[6-y]+y)/3
6y-y^2=(60-10y+y)/3
3(6y-y^2)=60-9y
18y-3y^2=60-9y
-3y^2+18y+9y-60=0
-3y^2+27y-60=0
-3(y^2-9y+20)=0
-3(y-4)(y-5)=0
y-4=0
y=4 ans.
x=6-4
x=2 ans (24)
y-5=0
y=5 ans.
x=6-5
x=1 ans (15)