Question 208418
Assume the problem is:
{{{(1/2)x}}} + {{{5/6}}} = {{{1 - (2/3)x}}}
Multiply equation by 6
 6*{{{(1/2)x}}} + 6*{{{5/6}}} = {{{6(1) - 6*(2/3)x}}}
Cancel the denominators
3x + 5 = 6 - 2(2x)
:
3x + 5 = 6 - 4x
:
3x + 4x = 6 - 5
:
7x = 1
x = {{{1/7}}}
:
:
See if this is true
{{{(1/2)(1/7)}}} + {{{5/6}}} = {{{1 - (2/3)(1/7)}}}
{{{(1/14)}}} + {{{5/6}}} = {{{1 - (2/21)}}}
{{{(1/14)}}} + {{{5/6}}} = {{{(21/21) - (2/21)}}}
Use a common denominator 42
{{{(3/42)}}} + {{{35/42}}} = {{{(42/42) - (4/42)}}}
{{{38/42}}} = {{{38/42}}}