<PRE><B>Question 209550</B>

Let the smallest integer be I
Then the 2nd and 3rd are (I + 2) and (I + 4)

Since the sum of the smallest and 3 times the second is 38 more than twice the 3rd, then we get:


I + 3(I + 2) = 2(I + 4) + 38


I + 3I + 6 = 2I + 8 + 38

4I – 2I =  46 – 6

2I = 40

I  =  20

The integers are: {{{highlight_green(20_22_24)}}}

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Check
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20 + 3(22)  = 2(24) + 38

20 + 66 =  48 + 38

86 = 86
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