Question 208720
Each of the integers h,m and n is divisible by 3. which of the following integers is always dividing by 9? 
I. hm
II. h + m
III. h + m + n

(A) I only (B) II only (C) III only (D) II and III only (E) I,II and III
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You can rule out II by 6 + 9 = 15, 6 and 9 
are both divisible by 3, but 15 is not 
divisible by 9,

You can rule out III by 6 + 9 + 15 = 30, 6, 
9 and 15 are all divisible by 3, but 30 is 
not divisible by 9,

However h and m each have a factor of 3, 
therefore hm must contain two factors of 3.  For 
example if h=6 and m = 12 then hm=6*12=72 
which is divisible by 9.

Therefore, the correct choice is (A), I only

Edwin</pre>