Question 209214
Jess has 3 more nickels than dimes for a total of $1.50. How many of each coin did he have?


Let the amount of dimes be D


Since he has 3 more nickels than dimes, then he has (D + 3) nickels


Since the coins total $1.50, then we have:

.1D + .05(D + 3) = 1.5


.1D + .05D + .15 = 1.5


.15D = 1.35


{{{D = 1.35/.15 = highlight_green(9)}}} dimes


Since he has 3 more nickels than dimes, then he has 9 + 3, or {{{highlight_green(12)}}} nickels