Question 209214
Jess has 3 more nickels than dimes for a total of $1.50. How many of each coin did he have?
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Quantity Eq: n = d + 3
Value Eq: 5n + 10d = 150 cents
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Substitute to solve for "d":
5(d+3)+10d = 150
15d + 15 = 150
15d = 135
d = 9 (# of dimes)
n = d+3 = 9+3 = 12 (# of nickels)
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Cheers,
Stan H.
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