Question 209454
{{{y=x^3-x^2}}} Start with the first equation.



{{{5x^2=x^3-x^2}}} Plug in {{{y=5x^2}}}



{{{0=x^3-x^2-5x^2}}} Subtract {{{5x^2}}} from both sides.



{{{0=x^3-6x^2}}} Combine like terms.



{{{0=x^2(x-6)}}} Factor out the GCF {{{x^2}}}



{{{x^2=0}}} or {{{x-6=0}}} Use the zero product property to set each factor equal to zero.



{{{x=0}}} or {{{x=6}}} Solve for 'x' in each equation.



So the solutions are {{{x=0}}} (with a multiplicity of 2) or {{{x=6}}}