Question 209422
Good  start
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Let  consecutive  EVEN  integers  be,,,x,,,,,x+2,,,,x+4
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then  equation  becomes,,,,8{(x) +(x+2)} = 8+12(x+4)
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simplify
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8{2x+2} = 8 +12x + 48
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16x +16 =8 +12x +48
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4x = 40
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x=10,,,integers  are,,,10,,,12,,,14
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check,,,8(10+12) = 8 + 12(14)
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8(22) =8 + 12(14)
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176 = 8+168 = 176,,,,ok
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NOTE,  the  relation x,,x+2,,x+4,,etc,,,,works  for  consecutive  EVEN  or  ODD  integers
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