<PRE><B>Question 209408</B>
how is this problem factored. 
3xy^2+11xy-20x
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Think of two numbers whose product is 3*-120 = -60
and whose sum or difference is 11
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The numbers are 15 and 4
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Rewrite the problem:
x(3y^2 + 11y - 20)
x(3y^2 + 15y - 4y - 20)
x(3y(y+5)-4(y+5))
x(y+5)(3y-4)
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Cheers,
Stan H.
Reply to stanbon@comcast.net</PRE>