Question 209274

12y^2-16y-3

{{{12y^2-16y-3}}}


We're looking for 2 factors that when multiplied gives us - 36 (c * a), and when added gives us - 16 (middle term of the trinomial)


These 2 factors are - 18 and + 2


Therefore, we restate the original trinomial, substituting - 18y and + 2y for - 16 (middle term of the trinomial)


We then have:    {{{12y^2 - 18y + 2y - 3}}}


Find the GCFs of the two expressions, and then factor each


6y(2y - 3) + 1(2y - 3)


The factors of 12y^2-16y-3 are then: {{{highlight_green((6y + 1)(2y - 3))}}}