Question 28978
It sounds like the path is constructed IN and not AROUND the garden, so
it diminishes the amount of gardent area.
Let the uniform width of the path be "x".
If you draw the picture you will see that the remaining garden space is
a rectangle with a width of 30-2x and a length of 20-2x.
EQUATION:
(30-2x)(20-2x)=400
2(15-x)2(10-x)=400
(15-x)(10-x)=100
150-25x+x^2=100
x^2-25x+50=0
*[invoke quadratic "x",1,-25,50]
Hope this helps
Cheers,
Stan H.