Question 209139
Find the lesser of two consecutive integers whose sum is greater than 16.


Let the lesser integer be I


Then the larger integer is: I + 1


Since the sum of both is greater than 16, then:


I + I + 1 > 16


2I  >  15


{{{I > 15/2}}} = {{{7.5}}}


Any number greater than {{{7.5}}} can be used as the lesser of the two numbers, as long as 1 is added to the lesser chosen number to get the larger number.