Question 209169
The function f is defined by y = f(x) = 2 ln 4x, 0:01 <= x >= 1 .
(a) Solve for x in terms of y, and hence and the formula for the inverse
function f^(-1)(x).
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y = 2*ln(4x)
ln(4x) = y/2
4x = e^(y/2)
x = (1/4)e^(y/2)
Interchange x and y to get the equation of the inverse.
y = (1/4)e^(x/2)
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Do
b) Write down the domain of f^(-1)
Since the Range of y = 2*ln(4x) is f(0.01)<y<=f(1) 
which is -6.438 < y < 2.7726
the Domain of f^-1(x) is -6.438 < x <= 2.7726



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Cheers,
Stan H.
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