Question 28932
original data: 150=Rt. So, t=150/R
Modified time and rate result in the following:
150=(R+20)(t-2)
Substitue for "t" to get:
150=(R+20)[(150/R)-2]
150=150-2R+3000/R-40
0=-2R^2+3000-40R
0=2R^2+40R-3000
0=R^2+20R-1500
*[invoke quadratic "R",1,20,-1500]
Hope this helps.
Cheers,
Stan H.