Question 208735
sqrt(2x+3) - sqrt(x+1) =1 
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Square both sides to get:
(2x+3) - 2sqrt[(2x+3)(x+1)] + (x+1) = 1
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Isolate the radical term:
[2sqrt[2x^2+5x+3] = 3x+4-1
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Square both sides:
4[2x^2+5x+3] = (3x+3)^2
8x^2 + 20x + 12 = 9x^2 + 18x + 9
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Solve for "x":
x^2 -2x -3 = 0
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Factor:
(x-3)(x+1) = 0
x = 3 or x = -1
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Checking those possible answers in sqrt(2x+3) - sqrt(x+1) =1 :
x = 3
This checks out
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X = -1 
This checks out
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Cheers,
Stan H.
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