<PRE><B>Question 208670</B>
twice the greater of two consecutive odd integers is 13 less than three times the lesser. find the intergers.


Let the smaller of the 2 numbers be S


Then the greater number would be S + 2


Since twice the greater of the 2 odd integers is 13 less than three times the lesser, we will have:


2(S + 2) = 3S - 13
 

2S + 4 = 3S - 13


2S - 3S = - 13 - 4


- S = - 17


{{{S = (-17)/-1=17}}}


Therefore, the smaller odd integer is {{{highlight_green(17)}}} and the larger consecutive odd integer is {{{highlight_green(19)}}} (17 + 2)

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Check
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Twice the greater integer, 19, is 38 (2 * 19)


3 times the lesser integer is 51 (3 * 17)


Twice the greater integer, or 38 is 13 less than 3 times the lesser integer, or 51 (51 - 13 = 38)

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