Question 208164
(x-3)^2+(x+2)^2=17
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x^2-6x+9 + x^2+4x+4 = 17  You have to add them up, not take the 1 at a time.
2x^2-2x+13 = 17
2x^2-2x+4 = 0
x^2-x+2 = 0
(x-2)*(x+1) = 0
x = 2
x = -1