Question 208081
Since "x is the number of years after 2000", this means that when the year is 2003, the value of x is x=3



So simply plug in x=3 into {{{P=13+45*ln(x)}}} to get: 



{{{P=13+45*ln(3)=13+45*1.0986=13+49.437=62.437}}}



So when {{{x=3}}}, {{{P=62.437}}}. So the percentage of spam in 2003 is 62.437%