Question 207960
 How can I do the factoring of the following: N to the forth power minus 4N to the 3rd power plus n minus 4
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{{{n^4 - 4n^3 + n - 4}}}
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Inspection is a start. Since the coefficients are 1,-4,1,-4, try 1 and -1, and 4 and -4.
If n=-1, that's an obvious zero, since it's 1+4-1-4.
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Divide by (n+1)
= {{{(n+1)*(n^3 -5n^2 + 5n - 4)}}}
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Try n = 4: 64 - 80 + 20 - 4 = 0 so (n-4) is a factor.
={{{(n+1)*(n-4)*(n^2 + n + 1)}}}