Question 207913
{{{2h^2-h-3=0}}} Start with the given equation



{{{(2h-3)(h+1)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{2h-3=0}}} or  {{{h+1=0}}} 



{{{h=3/2}}} or  {{{h=-1}}}    Now solve for h in each case



So the solutions are {{{h=3/2}}} or  {{{h=-1}}}