Question 207889
In a triangle, the height is 1 inch longer than twice its base. If the area of the triangle is 39 Sq inch, then how long is the base and what is its height? 
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Area = bh/2 = 39
bh = 78
b*(2b+1) = 78
2b^2 + b - 78 = 0
(2b + 13)*(b - 6) = 0
b = 6
h = 13