Question 207864
geometric  sequence ,,,t(n) = a(1) r^(n-1)
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given,,,t(4) =a r^(4-1) =ar^3 =8
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given,,,t(7) =ar^(7-1) = ar^6 =1
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(ar^6 =1)/(ar^3 = 8)
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r^(6-3) =1/8
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r^3 = 1/8,,,,take  cube  root
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r= .5 ,,,,,answer
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subst,,,,ar^3=8,,,,a*(.5)^3 =8,,,,,a=64,,,,answer
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check,,,,ar^3=8,,,,,(64)* .5^3 = 8,,,,,,ok
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ar^6=1,,,,,,(64)*.5^6 =1,,,,,ok
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to  find  t(10) =ar^(10-1) =ar^9 =(64)*.5^9 = .125 = 1/8,,,answer