Question 207805
please help me answer this equation {{{h(x)= (tan(1)-1)/1^3}}}
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1^3 = 1, so cancel that.
{{{h(x)= (tan(1)-1)}}}
Is it 1º? Or 1 radian?
If it's 1º, then
h(x)=~ 0.017455-1
=~ -0.9825449
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It it's 1 radian, then
=~ 1.5574 - 1
=~ 0.5574