Question 207751
use composite rule to differentiate the function
f(x)=exp (2/3 sin x)
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Let u = (2/3 sin(x))
Then du = (2/3 cos(x))dx
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f'(x) = [e^(2/3 sin(x)]*d/dx[(2/3 sin(x)]
f'(x) = [e^(2/3 sin(x))]*[2/3 cos(x)]
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Cheers,
Stan H.