Question 207755
if a sequence follows the same patterns as a, ar, ar^2... and t4=8 and t7=1
find a, r, and t10 
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t(4) = 8 = ar^3
t(7) = 1 = ar^6
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Divide t(7) by t(4) to get:
[ar^6]/[ar^3] = 1/8
r^3 = 1/8
r = 1/2
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Substitute into ar^3 = 8 to solve for "a":
a(1/2)^3 = 8
a(1/8) = 8
a = 64
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So, t(10) = ar^9 = 64(1/2)^9 = 1/8
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Cheers,
Stan H.