Question 207749
You are given the density of silver and told about a silver sphere that has a mass of 0.295g.

So you need to find the diameter of a sphere that with that mass.

First let's figure out what volume the sphere must be.
{{{10.5g/(cm^3) = 0.295g/(VolumeofSphere)}}}
{{{VolumeOfSphere = 0.295/10.5 = 0.0280952(cm^3)}}}

You are asked to find the sphere's diamter in mm. So let's convert the volume to (mm)^3

There are 10 mm/cm, so the converion from (mm)^3/(cm)^3 = 10*10*10 = 1000(mm)^3/(cm)^3

{{{VolumeOfSphere = 1000*.0280952 = 28.0952(mm)^3}}}
You are ready ro solve
{{{(4/3)*pi*r^3 = 28.0952}}}
{{{r^3 = (28.0952*3)/(4 * pi)}}}

Now just grind out the value for r.
Once you have that, you need to remember you were asked for the diameter. So just double the radius and you are there.