Question 207719
There's a problem with your question. There are no counter examples to prove the statement "The sum of any 2 odd numbers is even" wrong. 



It turns out that any odd number can be written in the form {{{2x+1}}} where 'x' is a whole number. Now let's say we have two odd numbers {{{y=2a+1}}} and {{{z=2b+1}}} where 'a' and 'b' are whole numbers. If we add them up, we get: {{{y+z=(2a+1)+(2b+1)=(2a+2b)+2=2(a+b)+2=2(a+b+1)=2k}}} where {{{k=a+b+1}}}



Now because even numbers fit the form {{{2x}}}, where 'x' is a whole number, this means that {{{2k}}} is an even number (since 'k' is a whole number). 



So it turns out that the sum of ANY two odd numbers is ALWAYS even. This is why no counter examples are possible.