Question 207697
t^2+6t+9
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Think of two numbers whose product is 9 and whose sum is 6.
The numbers are 3 and 3.
Replace the 6t by 3t + 3t to get:
t^2 + 3t + 3t + 9
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Factor the 1st two and the last two terms separately:
t(t+3) + 3(t+3)
Factor again to get the final answer:
(t+3)(t+3)
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Cheers,
Stan H.