Question 207564
figure out the GCF first. Here is the problem.
5y^5+31y^4+6y^3
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5,31, and 6 have no common factor other than "1":
y^5,y^4, and y^3 have a common factor of y^3
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Factor out the common factor to get:
y^3[5y^2 + 31y + 6]
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Factor the binomial:
= y^3[5y^2 +30y + y + 6]
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= y^3[5y(y+6)+ (y+6)]
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=y^3(y+6)(5y+1)
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Cheers,
Stan H.