Question 207402
The consecutive numbers can be expressed as {{{a}}} and {{{a+1}}}
given:
{{{3a = 2*(a + 1) + 4}}}
{{{3a = 2a + 2 + 4}}}
{{{3a = 2a + 6}}}
{{{a = 6}}}
{{{a+1 = 7}}}
The numbers are 6 and 7