Question 207406
I'll do the first one to get you started.



# 1



{{{2x^2=3x}}} Start with the given equation.



{{{2x^2-3x=0}}} Subtract 3x from both sides.



{{{x(2x-3)=0}}} Factor out the GCF 'x'



{{{x=0}}} or {{{2x-3=0}}} Set each factor equal to 0 (using the zero product property)



{{{x=0}}} or {{{2x=3}}} For the second equation, add 3 to both sides.



{{{x=0}}} or {{{x=3/2}}} For the second equation, divide both sides by 2 to isolate 'x'.



So the solutions are {{{x=0}}} or {{{x=3/2}}} (note: {{{1.5}}} the decimal form of {{{3/2}}})