Question 207322
w^3 + 1,,,pls  recognize  this  as  a  cube form,,a^3 +b^3,  which  factors  to :
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(a+b)*(a^2 -ab +b^2),,,,,now  with  a=w,,,,and  b=1,,,we  find
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(w+1) * (w^2 -w + 1)
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The  problem  probably  wants  us  to  use  polynomial  division,  so  let's  try  that.
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Remember  to  "fill"  all  the  terms
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,,,,,,,,,,,,,,,,w^2,,-w,,,+1
,,,,,,,,,,____________________________________
(w+1),,,,[ w^3 +0 w^2 +0w +1
.,,,,,,,,,,w^3 +w^2
.,,,,,,,,,_________
.,,,,,,,,,,,,,,-w^2 + 0w
,,,,,,,,,,,,,,,-w^2 -w
,,,,,,,,,,,,,,,__________
,,,,,,,,,,,,,,,,,,,,,+w  +1
,,,,,,,,,,,,,,,,,,,,,+w  +1
,,,,,,,,,,,,,,,,,,,,,,______
,,,,,,,,,,,,,,,,,,,,,,,,,,0...........NOTE  REMAINDER = 0
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as  this  matches  factoring  form,  this  is  correct  answer

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