Question 207236
[(4x^3 + 8x)/(3x)] / [(4x^2 + 8)/(6x^2)]



[(4x^3 + 8x)/(3x)] * [(6x^2)/(4x^2 + 8)]



[(4x(x^2 + 2))/(3x)] * [(3x*2x)/(4(x^2 + 2))]



x * 2x


2x^2


Answer: 

[(4x^3 + 8x)/(3x)] / [(4x^2 + 8)/(6x^2)] = 2x^2