Question 206815
DRAW  an  equilateral  triangle.  Draw  a  straight  line.  Set  compass at  a  convenient  distance  and  keep  it  there.
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On  straight  line, mark  a  starting  point. Set  compass  point  in  the  mark  and  scribe  the  line  in  one  spot to  indicate  the  distance. Now  from  the  initial mark  strike  an  arc,  about  where  the  vertex  might  be.  
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Move  to  the  other mark  on  the  line  and  draw  an  arc to cross  the  first  arc.   This  should  be  the  vertex.
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to  check,  set  the  compass  to  any  side,  and  check  other 2 sides. Allow  some  error  for  drafting.
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To bisect, we  assume  they  mean  one  angle. From  both vertex  on  the  original line  strike  an  arc  with  the  compass  set  at  slightly  more  than   midway between. Draw  a  straight  line   between the  arc  intersections.  This  should  be  a  perpendicular bisector  of  the  base,  and  should  pass  thru  the  top  vertex.
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If  they  want you  to  bisect  all  of  the  angles,  repeat  for the  other  angles.
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For  the  second  problem,  Draw  a  right  triangle.
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For  30 degrees,  mark  one  of  the  leg  angles  30. The  other  leg  is  the  90 degree  angle. Either  using  the  trig  tables,  or  remembering  the  info  for  standard  triangles, we  know that  the  hypotenuse(side opposite  right angle)  is = 2,,,the  side  opposite  the  30 deg  angle  is = 1,  and  the  other  side is = sqrt 3.
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The  tan  of  30 is opposite  side / adjacent  side, or 1/sqrt 3 = .577
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For  60 degrees,  use  the  same  picture.  The  odd  angle  is  60 degrees. (the  one  not  30  or  90).  
The  tan  of  60 = sqrt3 / 1= 1.732
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for  45  degrees,  we  need  a  new  sketch. Again  a  rt triangle, sides labeled 1, 1, and sqrt2,(with  sqrt2 being  the  hypotenuse)
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The  tan  of  45, is  again  opposite /adjacent, or 1/1= 1 
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Hopefully  this  helps
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keep  up  the  good  work