Question 206908

Let the first even integer be f

Then the 2nd, 3rd, & 4th are f + 2, f + 4, & f + 6, respectively


Since the sum of the 2nd and 4th is 76, then we get: (f + 2) + (f + 6) = 76


2f + 8 = 76


2f = 68


{{{f = 68/2 = 34}}}


Since the 1st EVEN INTEGER is 34, it follows that the FOUR CONSECUTIVE EVEN INTEGERS are {{{highlight_green(34)}}},{{{highlight_green(36)}}},{{{highlight_green(38)}}} & {{{highlight_green(40)}}}.


Check:

Sum of 2nd integer and 4th integer is 76

2nd EVEN INTEGER = 36   ;   4th EVEN INTEGER = 40

Sum of 2nd and 4th EVEN INTEGERS is 76 (36 + 40).