<PRE><B>Question 206848</B>
Steve has 36 coins consisting of dimes and nickels. If the value of the coins is $3.10, then how many dimes does he have?
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Quantity Eq: d + n = 36
Value Eq:  10d +5n = 210 cents
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Multiply thru the Quantity equation by 5 to get:
5d + 5n = 5*36
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Subtract that from the Value Eq. to get:
5d = 210-5*36
d = 42-36
d = 6 (# of dimes)
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Cheers,
Stan H.</PRE>