Question 206804
Let h = Henry's present age
Let d = Daisy's present age
:
Just write an equation for what it says:
"Half of Henry's age added to 1/3 of Daisy's age is 11 years."
{{{1/2}}}h + {{{1/3}}}d = 11
Multiply by 6 to get rid of the fractions, results:
3h + 2d = 66
:
" Six years from now the sum of their ages will be 40 years"
(h+6) + (d+6) = 40
h + d + 12 = 40
h + d = 40 - 12
h + d = 28
:
 how old is each?
Multiply the above equation by 2 and subtract from the 1st equation
3h + 2d = 66
2h + 2d = 56
---------------subtraction eliminates d, find h
h = 10
:
:
I'll let you find d, then check the two solutions in both equations