Question 206762


{{{3(x-2)^2=48}}} Start with the given equation.



{{{(x-2)^2=(48)/(3)}}} Divide both sides by {{{3}}}.



{{{(x-2)^2=16}}} Reduce.



{{{x-2=""+-sqrt(16)}}} Take the square root of both sides.



{{{x-2=sqrt(16)}}} or {{{x-2=-sqrt(16)}}} Break up the "plus/minus" to form two equations.



{{{x-2=4}}} or {{{x-2=-4}}}  Take the square root of {{{16}}} to get {{{4}}}.



{{{x=2+4}}} or {{{x=2-4}}} Add {{{2}}} to both sides.



{{{x=6}}} or {{{x=-2}}} Combine like terms.



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Answer:



So the solutions are {{{x=6}}} or {{{x=-2}}}.