Question 206737
3x(2x+1)=18
distributing the 3x to terms inside parenthesis:
6x^2 + 3x = 18
dividing both sides by 3:
2x^2 + x = 6
2x^2 + x - 6 = 0
factoring the left side:
(2x-3)(x+2) = 0
Solving for x:
x = {3/2, -2}