Question 206672


{{{(3x-1)(-x^2+4x+2)}}} Start with the given expression.



{{{3x(-x^2+4x+2)-1(-x^2+4x+2)}}} Expand.



{{{(3x)*(-x^2)+(3x)*(4x)+(3x)*(2)+(-1)*(-x^2)+(-1)*(4x)+(-1)*(2)}}} Distribute.



{{{-3*x^3+12*x^2+6*x+x^2-4*x-2}}} Multiply.



{{{-3*x^3+13*x^2+2*x-2}}} Now combine like terms.



 So {{{(3x-1)(-x^2+4x+2)}}} expands to {{{-3*x^3+13*x^2+2*x-2}}}.



In other words, {{{(3x-1)(-x^2+4x+2)=-3*x^3+13*x^2+2*x-2}}}.