Question 206170
(a)  each  rhombus  has  4  sides  of 10 each  or  perimeter  of  40 inches
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(b)Per  of  qtr  circle = 18 +18 +1/4 circumference
cir =2*pi*r=2*3.14*18 = 113.04,,,,,1/4 cir = 28.26
per  of  qtr  circle = 18+18+28.26 = 64.26 inches
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(c)Each  Rhombus  has  a  base  of  10  and a height of 7,,,a=Bh=(10)(7)=70 sq in
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(d)Area  of  entire  circle = pi*r^2=3.14 * 18^2 = 1017.26
1/4  of  Area = 1/4 * 10.17.26 = 254.34 sq in
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(e)Net  Area = Area 1/4  circle - 2*  Area  each  Rhombus
A= 254.34 -2(70) = 114.24 sq in