Question 206464
If f(x)=1-3x and g(x)=1/(x^2+1),find f(g(0)) and g(f(1))
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f[g(o)] = f[1] = 1-3 = -2
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g[f(1)] = g[-2] = 1/(2^2+1) = 1/5
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Cheers,
Stan H.