Question 206352
how to do you find all values of y satisfying this equation? 
7/(y-2)= -8 -3/(y-1)
-------------------------
Multiply both sides by (y-2)(y-1) to get:
---
7(y-1) = -8(y-2)(y-1) - 3(y-2)
------------------------------
7y-7 = -8(y^2-3y+2) -3y + 6
7y - 7 = -8y^2 + 24y - 16 -3y + 6
8y^2-14y+3 = 0
Factor using athe AC Method:
8y^2-12y-2y+3 = 0
4y(2y-3)-(2y-3) = 0
(2y-3)(4y-1) = 0
Solve for "y":
y = 3/2 or y = 1/4
========================================
Cheers,
Stan H.
========================================