Question 205982
{{{ ((x^2 - 1)/ (6x)) *( ( 3x^2)/ (x^2 + x)) }}}

{{{ 6x / (3x) = 2 }}} and  {{{ 3x^2 / (3x) = x }}} , so

{{{ ((x^2 - 1)/ (6x)) *( ( 3x^2)/ (x^2 + x)) =  ((x^2 - 1)/ 2) *( x/ (x^2 + x))  }}} = (factoring)
{{{  ((x+1)(x-1)/ 2) *( x/ (x(x+1))) =  ((x-1)/ 2) *( x/ x) = ((x-1)/ 2) }}}